豹子 2007-6-23 10:29
MD5算法研究(2)
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常数ti可以如下选择: \|M zQ
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在第i步中,ti是4294967296*abs(sin(i))的整数部分,i的单位是弧度。(4294967296等于2的32次方)
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所有这些完成之后,将A、B、C、D分别加上a、b、c、d。然后用下一分组数据继续运行算法,最后的输出是A、B、C和D的级联。 L7` {?z f5U DH
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当你按照我上面所说的方法实现MD5算法以后,你可以用以下几个信息对你做出来的程序作一个简单的测试,看看程序有没有错误。 #f5}}uY'Q
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MD5 ("") = d41d8cd98f00b204e9800998ecf8427eh\o G#y
MD5 ("a") = 0cc175b9c0f1b6a831c399e269772661
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MD5 ("abc") = 900150983cd24fb0d6963f7d28e17f72
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MD5 ("message digest") = f96b697d7cb7938d525a2f31aaf161d0j\i-O}4{k7@
MD5 ("abcdefghijklmnopqrstuvwxyz") = c3fcd3d76192e4007dfb496cca67e13b
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MD5 ("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789") = L?%?2zJ Xz7D,f
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MD5 ("123456789012345678901234567890123456789012345678901234567890123456789
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01234567890") = 57edf4a22be3c955ac49da2e2107b67a avIJR$`{s7Jb